What is the range of the function y=
= VX+5?
Oy2-5
Oy20
O yzv5
Oy25

A)  y² -5

The range of the given function x = y² -5

Step-by-step explanation:

Explanation:-

Given f(x) = √x +5

Let y = f(x) = √x +5

    y = √x +5

   squaring on both sides, we get

⇒  y² = x +5

⇒ x = y² -5

The range of the given function x = y² -5

i can

step-by-step explanation:

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42