The cost, C dollars, to produce a school yearbook is given by the equation c= 7500 + 8n, where n is the number of yearbooks printed. A. what does each term on the right side of the equation represent?
B. Suppose there is $ 11 500 to spend on yearbooks. How many can be purchased?
C. How many yearbooks could be produced for $20 000
D. How much would 700 yearbooks cost?

A.  see below

B.  500 yearbooks

C.  1562 yearbooks

D.  $13,100

Step-by-step explanation:

A.  The first term (7500) is probably a flat fee for the production of yearbooks.  No matter how many yearbooks you will always have to pay that amount.  The second term (8n) is the cost of each individual yearbook.

B.  For this problem you need to use the equation.  Since the number given to us is an amount of money, it will go into the variable C.  Solve for n.

C = 7500 + 8n

11,500 = 7500 + 8n

4,000 = 8n

500 = n

You can purchase 500 yearbooks.

C.  For this problem, the amount is again in dollars so it will go into the variable C.  Solve for n.

C = 7500 + 8n

20,000 = 7500 + 8n

12,500 = 8n

n = 1,562.5

Since the number is not a whole number, round down.  You can purchase 1562 yearbooks.

D.  For this problem, the given value is not in dollars so the value will go into n.  Solve for C.

C = 7500 + 8n

C = 7500 + 8(700)

C = 7500 + 5600

C = 13,100

The cost of 700 yearbooks would be $13,100.

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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