A submarine traveling 100 km from the shore decended 1/10 km below sea level. Then it ascended about 3/5 km the next it again descended by 9/10 km what is the current position with respect to the sea level what is the horizontal distance of the submarine from sea shore?

Horizontal displacement = 100 km

Position with respect to sea level = -0.4km

Step-by-step explanation:

Let the displacement downwards be negative displacement and displacement upwards be positive.

The horizontal distance from the shore remains constant whereas the displacement from the sea level varies as the submarine moves.

The upward displacement = 3/5 km

Downward displacement = - 1/10 km and - 9/10 km

Total displacement = 3/5km - 1/10 km - 9/10km = - 2/5 km = - 0.4 km

Horizontal distance from the shore = 100km

( ͡° ͜ʖ ͡° ) copy and   paste it

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5