Mathematics, 23.06.2020 22:01 santosv3136

Flight 4581 travels daily from Pittsburgh to San Antonio. The flight is due into San Antonio at 5:07 p. m. The following list gives the Flight 4581 arrival time relative to 5:07 p. m. (in minutes) for a selection of 9 days. (A negative number means that the flight arrived early.) 21, 39, 37, 25, 6,-6, -4, 40, 37 Send data to Excel (a) What is the mean of this data set? If your answer is not an integer, round your answer to one decimal place. an integer, round your answer to one decimal place.
zero modes
(b) How man ndicate the number of mo vasluers) of the mode modes does the data set have, and what are eir values?

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Answer from: t0ri21

Question:

Flight 4581 travels daily from Pittsburgh to San Antonio. The flight is due into San Antonio at 5:07 p.m. The following list gives the Flight 4581 arrival time relative to 5:07 p.m. (in minutes) for a selection of 9 days. (A negative number means that the flight arrived early.) 21, 39, 37, 25, 6,-6, -4, 40, 37 Send data to Excel

(a) What is the mean of this data set? If your answer is not an integer, round your answer to one decimal place. an integer, round your answer to one decimal place.

b) How many modes does the data set have? and what are their values

a) 21.2

b) Value of mode = 37

It contains just one mode

Step-by-step explanation:

Given:

x = 21, 39, 37, 25, 6,-6, -4, 40, 37

n = 9

a) Find the mean

Mean is the average value of a dataset.

Mean = Σx/n

Mean = $\frac{21+39+37+25+6+(-6)+(-4)+40+37}{n}$

$= \frac{195}{9}$

= 21.667

The question says one decimal place.

Therefore, mean = 21.7

b) The mode of a dataset is the value that appears most frequently.

We have the following datasets:

21, 39, 37, 25, 6,-6, -4, 40, 37

The value that appears most frequently here is 37.

37 appeared twice while the rest appeared just once.

Therefore the dataset contains just one mode

Answer from: Quest

The answer would be option 4

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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