Find a general solution to the differential equation. y double prime (theta )plus 9 y (theta )equals 2 secant cubed 3 thetay′′(θ)+9y(θ)=2sec33θ The general solution is y (theta )y(θ)

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.