A web based software company is interested in estimating the proportion of individuals who use the Firefox browser. In a sample of 200 of individuals, 19 users stated that they used Firefox. Using this data, construct a 99% confidence interval for the proportion of all individuals that use Firefox. a) What is the lower limit on the 99% confidence interval? Give your answer to three decimal places. b) What is the upper limit on the 99% confidence interval? Give your answer to three decimal places. c) Google states that the proportion of all individuals that use Firefox is 0.2. Based on the interval above, does the Google claim seem reasonable?1. No because 0.2 is inside the interval. 2. Yes because 0.2 is not inside the interval. 3. Yes because 0.2 is inside the interval. 4. No because 0.2 is not inside the interval. d) If you hadn't already taken the sample listed above, what sample size would be required so that the width of the 99% confidence interval would be at most 0.02 units wide? Be as conservative as possible with your answer!

a) 0.119 (11.9%)

b) 0.261 (26.1%)

c) Yes because 0.2 is inside the interval.

d) n = 2,554

Step-by-step explanation:

We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.19.

The standard error of the proportion is:

The critical z-value for a 99% confidence interval is z=2.576.

The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 99% confidence interval for the population proportion is (0.119, 0.261).

c) The value 0.2 is included in the interval. This means that is one of the values that, with 99% confidence, the true proportion can take.

d) We have to calculate the minimum sample size n needed to have a margin of error below 0.02.

To do that, we use the margin of error formula in function of n:

The minimum sample size to have this margin of error is n = 2,554.

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step-by-step explanation:

answer: what is the conflict?

step-by-step explanation:

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