The given line passes through the points (-4, -3) and (4. 1)
What is the equation, in point-slope form of the line that is
perpendicular to the given line and passes through the
point (-4, 3)?
V-3 -2(x+4)
3-
2-
+
Oy-3 =-{(x+4)
Ov-3 = {(x + 4)
-2
y-3 =2(x + 4)
-3
(-3)

9514 1404 393

  y -3 = -2(x +4)

Step-by-step explanation:

The slope of the given line is ...

  m = (y2 -y1)/(x2 -x1)

  m = (1 -(-3))/(4 -(-4)) = 4/8 = 1/2

The perpendicular line will have slope -1/(1/2) = -2.

__

The point-slope equation of the line with slope m through point (h, k) is ...

  y -k = m(x -h)

For point (-4, 3) and slope -2, the equation is ...

  y -3 = -2(x +4)

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation: