Compute i^1+i^2+i^3+...+ i^97 + i^98+i^99.

If , then , , and .

We can break up the given sum into 25 groups (after adding and subtracting ):

We have

and in each group, we can pull this out as a factor. For example,

So the entire sum reduces to the remaining term,

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]