David drops a ball from the top of a building with a height of 64 feet. The height (h) of the ball, in feet, after (t) seconds can be found using
the formula h=-16° +64. How long will it take the ball to reach the
ground?
A)3 sec
B)2sec
C)1 sec
D)none

Step-by-step explanation:

The position formula for this is actually

It says, in not so may words, that the object was dropped under the influence of gravity from a height of 64 feet. When it hits, the ground, it will not be above ground at all anymore...it will be ON the ground and have a height of 0. Therefore, if we set the position function equal to 0 and solve for t, we are finding out how long it will take for the object to hit the ground.

and

and

and

t = 2

It takes 2 seconds for the object to hit the ground from 64 feet up.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x