Aramis showed the division of 6p2 + 9p + 3 by 3p. A + 3 + B What are the values of A and B? A = 2p and B = p A = 3p and B = p A = and B = A = 2p and B =

D) A = 2p and B = 1/p

Step-by-step explanation:

To divide this,

we first see how many times 3p will go into 6p².

It will go in 2p times; this goes up top of the problem.

Multiplying back through, we have

Subtracting this from the first term under the box, we have

 This cancels.  Bring down the next term, 9p.

See how many times 3p goes into 9p =

it goes in 3 times.  This goes up top, beside the 2p.  We separate them with a +, since the 3 is positive.

Multiplying back through, we have 3(3p) = 9p.  

Subtract this from the line above; 9p-9p = 0.  

Bring down the last term, 3.  

Since this is not 0, this is the remainder.  

This gives us

2p + 3 R 3;

writing this as a rational expression, we have

The remainder term, , will simplify to 1/1p or 1/p;

this gives us

Therefore, the answer is  A = 2p and B = 1/p

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