What is the result when 4x^3+5x^2+13x+34x 3 +5x 2 +13x+3 is divided by 4x+14x+1?

38^3+10^2+26x+3 over 18x+1

Step-by-step explanation:

Start by adding x's that are alike together.

4x^3+34x^3= 38^3

then do the same to the other x's

5x^2+5x^2= 10^2

Last x's

13x+13x=26x

For the final equation, you should have

38^3+10^2+26x+3

For the bottom equation, you do the same thing.

4x+14x= 18x

Final equation, really easy, is 18x+1

For the final answer you should have

38^3+10^2+26x+3 over 18x+1

Lmk if it helps!! :)

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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