What is the vertex of the quadratic function below?
y = 3x2 - 12x+17

D (2, 5)

Step-by-step explanation:

To find the vertex of the quadratic function , we will follow the steps below

(x,y) =  [-b/2a  , f(-b/2a)]

x = -b /2a         y = f(-b/2a)

The standard equation of a quadratic equation is  y =ax² + bx + c

compare the above with the equation given, y = 3x² - 12x + 17

a = 3   b= -12   and c= 17

x = -b/2a

x = -(-12)/2(3)

x = 12/6

x = 2

y = f(-b/2a)

y = f (-b/2a) = f(x) = f (2)

y = f(x) =3x² - 12x + 17

To find f(2) simply mean to substitute x = 2 into the quadratic function above. That is;

f(2) = 3(2)² - 12(2) + 17

f(2) =12-24 + 17

f(2) =5

x = 2   and    y  = 5

(x,y)  = (2, 5)

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: