compute an interval estimate with 90% confidence for the mean time to complete an employment test. Assuming a population standard deviation of three hours, what is the required sample size if the error should be less than a half hour

The required sample size 'n' = 97 .41 hours

Step-by-step explanation:

Explanation:-

Given standard deviation of the Population 'σ' = 3 hours

Given the Margin of error =

The Margin of error is determined by

Given level of significance ∝ = 0.10 or 0.90

Z₀.₁₀ = 1.645

Cross multiplication , we get

√n =  9.87

Squaring on both sides, we get

n = 97.41 hours

Final -

The required sample size 'n' = 97.41 hours

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: