Can anyone help me with this problem?

Step-by-step explanation:

What you are looking for is the simplification of f(x) divided by g(x). This can be easily accomplished with synthetic division. If we are dividig the quadratic by x - 1, we will use the fact that if x - 1 = 0, then x = 1. We will put that 1 outside the "box" and put the coefficients from the quadratic inside the "box" and do the division synthetically. The coefficients on the quadratic terms are 2, 1, and -3:

1 | 2     1     -3

We begin by bringing down the first number, a 2, and multiplying it by the 1 in the box and putting the product up under the 1:

1 |  2     1     -3

           2        

    2

Now we add down the column:

1 |  2     1     -3

          2        

    2     3

Now multiply the 3 by the 1 outside the box and put that product up under the -3 and then add down that column:

1 |  2     1     -3

          2     3

   2      3     0

Because we have a 0 remainder, that means that the quadratic was evenly divisible by x - 1.  What we have left is called a depressed polynomial. It takes on the x values at one degree lesser than what we started with. Namely, it will be 2x + 3.

2x + 3 is what we get when we divide the quadratic by x - 1. BUT because we started off with x - 1 in the denominator, even though we divided it away to simplify, we still have to take into account that the value of 1 makes the denomiator go to 0, which is never allowed in math.

So the answer you want is the first one!

yes. we do proportions in probabilities.