Two fair dice are tossed and the number on each die is recorded, e. g. (3,2) indicates the first die had 3 and the second die had a 2. In total, there are 36 (equally likely) outcomes in the sample space. What is the probability the sum of the two dice is 7 or 11? Group of answer choices

P(7 or 11) = 0.2222

Step-by-step explanation:

First let's find the cases where we get a sum of 7 and a sum of 11:

The cases where we get a sum of 7 are:

(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)

And the cases where we get a sum of 11 are:

(5,6), (6,5)

So we have a total of 8 cases among the 36 total possible outcomes.

So the probability of the sum of the two dice being 7 or 11 is:

P(7 or 11) = 8 / 36 = 0.2222

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later