Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest integer, then which equation could be used to solve the problem?

The three integers are 7, 9, 11.

The equation is: 2x + x + 4 = 25

Step-by-step explanation:

The problem asks to use x to represent the smallest of the three integers.

Odd integers are 2 units apart, such as 1, 3, 5, 7. The difference between consecutive odd integers is 2.

Since the smallest odd integer is x, then the next larger one is x + 2. The largest odd integer is x + 2 + 2, or x + 4.

The three odd integers are

x, x + 2, x + 4

The problem then states "the sum of the largest and twice the smallest is 25."

The largest one is x + 4.

Twice the smallest is 2x.

Their sum is 2x + x + 4.

That sum equals 25.

2x + x + 4 = 25

3x + 4 = 25

3x = 21

x = 7

The smallest integer is 7.

Then x + 2 = 7 + 2 = 9,

and x + 4 = 7 + 4 = 11.

The three integers are 7, 9, 11.

The equation is: 2x + x + 4 = 25