The first and last terms of an AP are 1 and 121 respectively. Find
i the number of terms in the AP
if the common difference between them if
the sum of its terms is
b 671
d 1281
a 549
c976

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

go hook jvc hgv cj xk jvc 6756

1 3 5

step-by-step explanation:

i took the test: )