A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

Where:

- Initial height of the ball, measured in feet.

- Initial speed of the ball, measured in feet per second.

- Gravitational constant, equal to .

- Time, measured in seconds.

Given that , , and , the following second-order polynomial is found:

The roots of this polynomial are, respectively:

and .

Both roots solutions are physically reasonable, since represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

47 - 90 = 43

43 - 180 = x

x = 137