You draw a simple random sample of 100 taxi drivers living in New York City. You wish to test whether mean time spent driving for New York City taxi drivers is equal to 7 hours. You obtain a test statistic of 2.4. Using a 1% significance level, what is the outcome of this test

The degrees of freedom are given by:

And the p value would be given by:

For this case we see that the p value is higher than the significance level so we don't have enough evidence to reject the null hypothesis and then the true mean is not significantly different from 7 at the significance level given

Step-by-step explanation:

Data given and notation  

represent the sample standard deviation for the sample  

sample size

represent the value to test

represent the significance level

t would represent the statistic

represent the p value

Hypothesis to test

We want to test if the true mean is iequal to 7 or no, the system of hypothesis would be:  

Null hypothesis:  

Alternative hypothesis:  

The statitic is given by:

 (1)  

For this case we know that the statistic is:

The degrees of freedom are given by:

And the p value would be given by:

For this case we see that the p value is higher than the significance level so we don't have enough evidence to reject the null hypothesis and then the true mean is not significantly different from 7 at the significance level given

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

if you need , reply with more info. u.