The U. S. Department of Housing and Urban Development publishes data on the fair market monthly rent for existing one-bedroom housing by metropolitan area (The Federal Register, April 30 1997). The standard deviation for the monthly rent is about $80. Assume that a sample of metropolitan areas will be selected in order to estimate the population mean of the monthly rent for existing one-bedroom housing. Use 95% confidence. a. How large should the sample be if the desired margin of error is $25?

So the answer for this case would be n=247 rounded up to the nearest integer

Step-by-step explanation:

We know that the standard deviation is :

represent the deviation

The margin of error is given by this formula:

   (a)

And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

  (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution and the critical value would be , replacing into formula (b) we got:

So the answer for this case would be n=247 rounded up to the nearest integer

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts