American Medical Association wants to estimate the proportion of medical doctors who had a solo practice. How many doctors should be included in the study if the association wants 99% confident that the estimate is within 5 percentage point of the true population proportion?

The number of doctors 'n' = 6.76

Step-by-step explanation:

Explanation:-

Given Estimate of the true population proportion = 5 % = 0.05

Given level of significance ∝ = 99% or 1%

Z₀.₀₁ = 2.576

The margin of error is determined by

we know that

Cross multiplication , we get

√n = 0.2576≅0.26

squaring on both sides,we get

n = 0.0676 X 100

n=  6.76

Final -

The number of doctors 'n' = 6.76

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answer:

probably the same as it is today since you did not eat the corn dogs yet

step-by-step explanation: