What is the probability of rolling a dice and getting either a 1 or 2 and flipping a coin and getting a heads?

This is approximately equal to 0.167

Explanation:

A = event of getting either a 1 or 2

P(A) = probability event A occurs

P(A) = 2/6 = 1/3, since there are two ways to get "1 or 2" out of six total

B = landing on heads

P(B) = 1/2, there are two sides and only one is heads

P(A and B) = probability getting a 1 or 2 and flipping heads on a coin

P(A and B) = P(A)*P(B) only possible if A and B are independent

P(A and B) = (1/3)*(1/2)

P(A and B) = (1*1)/(3*2)

P(A and B) = 1/6

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°