And, S2 inutes)
In the table shown, the sum of each row is shown to the right of the row and the sum of each column is
shown below the column.
tion 1
tion 2
K
J
tion 3
J
K
5
13
tion 4
tion 5
K
J
L
L
tion 6
L
15
tion 7
tion 8
11
7
15
tion 9
tion 10
tion 11
What is the value of L?
tion 12
tion 13

Correct Question

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

it’s the first one your welcome