Can u guys PLEASE answer this question ASAP. A line passes through the point (2,4) and has a gradient 2. Find the y-coordinate of the point on the line when x=3

y=2

Step-by-step explanation:

Make an equation of straight line by using the formula :y= mx+c

put the x-value of point (2,4) which is 2 and the gradient,m which is 2 into the straight line equation:

y=2x +c

So you need to find the y-intercept to complete the equation, therefore:

when y=0,

0=2(2)+c

c=-4

next the question ask to find the y-coordinate when x =3, therefore you just need to replace x in the equation with 3:

y=2(3)-4

y=4

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer: sorry i can't you.

step-by-step explanation: