Write the rationalized expression of: sqrt9/sqrt3+sqrtx

3 sqrt(3) - 3 sqrt(x)

3  - x

Step-by-step explanation:

sqrt(9) = 3

so writing the expression as

3

sqrt(3) + sqrt(x)

Multiply by the conjugate, sqrt(3) - sqrt(x) in the numerator and denominator

3                            sqrt(3) - sqrt(x)

*

sqrt(3) + sqrt(x)    sqrt(3) - sqrt(x)

Foil the denominator

3 sqrt(3) - 3 sqrt(x)

sqrt(3) sqrt(3) + sqrt(3x) - sqrt(3x) - sqrt(x^2)

Simplify

3 sqrt(3) - 3 sqrt(x)

3  - x

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.