Peter’s teacher says he may have his report card percentage based on either the mean or the median and he can drop one test score if he chooses. 84%, 71%, 64%, 90%, 75%, 44%, 98% Which measure of center should Peter choose so he can have the highest percentage possible?

Go with the mean and remove the lowest score

Step-by-step explanation:

84%, 71%, 64%, 90%, 75%, 44%, 98%

First find the mean, which is add all the numbers and divide by the number of numbers

(84+ 71+ 64+ 90+ 75+ 44+98)/7

526/7 =75.14

If we drop one score, we would drop the lowest

(84+ 71+ 64+ 90+ 75+98)/6

482 /6 = 80.33

If we use the median, we take the middle, so put the scores from lowest to highest

44%,  64%,71%,     75%,      84%,90% , 98%

Without removing a score the median is  75%

Removing the lowest score

 64%,71%,     75%,      84%,90% , 98%

The median is between 75 and 84

(75+84)/2 = 79.5 %

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

yes

step-by-step explanation: