Factor the polynomial below. 9x^2-1 A. (-1)(9x-1) B. (3x-1)(3x-1) C. (3x-1)(3x+1) D. (x-1)(9x+1)

(3x-1) (3x+1)

Step-by-step explanation:

9x^2-1

Rewriting as

(3x)^2 - 1^2

This is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(3x-1) (3x+1)

the answer is d. (1.2, -4.7) on edgn

hope this !

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