If f(x) = 3x-1 + 4 and g(x) = 4x - 7, what is (f - g)(x)? O A. (*- g)(x) = 34-1 - 4x-11
O B. (8-9)x)= 3x-1 – 4x - 3
O C. (8-9)(x) = 3x-1 - 4x + 3
O D. (-9)(x) = 3x-1 - 4x +11

the answer

b. they are parallel and will never intersect.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the answer is no solution, glad i could .

the answer is a, biohazard symbol