If sin theta =6/10,such that theta is less or equal to 90° find the value of
a. sin theta +cos theta
b. tan theta + 1

a right angle has one right angle and two acute angles

letting one acute angle be theta and the other acute angle be (90°-theta)

sine is the ratio of opposite side and hypotenuse right angle theta it is written as sine = opposite/ hypotenuse

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

what is the model?

step-by-step explanation: