What is the slope of the line that contains the points (-2, 2) and (3, 4)?

2/5

Step-by-step explanation:

The slope is given by

m= (y2-y1)/(x2-x1)

  = (4-2)/(3 - -2)

   = 2/(3+2)

    = 2 /5

We are given the points (-2, 2) and (3, 4) to solve.

Slope formula: y2-y1/x2-x1

4-2/3-(-2)

2/5

Therefore, the answer is 2/5

Best of Luck!

hi friend

here is your answer

there are two angles that are alternate interior angle with angle 9

the angle 15 and angle 7 are alternate interior angle with angle 9.

hope it is for you so mark my answer as a brainliest

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."