HELP PLEASEFor a quadratic equation of the form 0 = ax2 + bx + c to have two zeros, what must be true?

Option (4)

Step-by-step explanation:

If a quadratic equation is represented by,

ax² + bx + c = 0

Then discriminant of this equation will be = b²- 4ac

Discriminant of a quadratic equation tells the type of roots the equation has.

1). If b² - 4ac > 0,

  Equation will have two distinct real roots

2). If b² - 4ac = 0

  Equation will have one real root

3). If b² - 4ac < 0

  Equation will have no real roots or there will be two imaginary roots.

For two real roots,

b² - 4ac > 0

b² > 4ac

Therefore, Option (4). 4ac < b² will be the answer.

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.