Solve for x. − 15 x + 60 ≤ 105 AND 14 x + 11 ≤ − 31

We know −15x+60≤105 and 14x+11≤−31

−15x+60≤105(Condition 1)

−15x+60−60≤105−60(Subtract 60 from both sides)

−15x≤45

−15x /−15 ≤ 45 /−15  (Divide both sides by -15)

x≥−3

14x+11≤−31(Condition 2)

14x+11−11≤−31−11(Subtract 11 from both sides)

14x≤−42

14x /14 ≤ −42 /14  (Divide both sides by 14)

x≤−3

x≥−3 and x≤−3

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x= -3

Step-by-step explanation:

-15 x + 60 ≤ 105 ⇒ -15x ≤ 45 ⇒ x≥ -3

14 x + 11 ≤ − 31 ⇒ 14x ≤ -42 ⇒ x ≤ -3

x ≤ -3 and x≥ -3

x= -3 is the solution

step-by-step explan mxfcg'k; uafwgzfgjhklhgation: