A group of tourists can be sorted into tour boats in groups of 4 or in groups of 6. In either case, there are no empty seats. Find the number of tourists if there are more than 25 and fewer than 45.

there are 36 tourists.

Step-by-step explanation:

Ok, we have two integer numbers:

T, the number of tourists and S, the number of seats.

Such that, if we divide the tourists into groups of 4 and in groups of 6, we end with no empty seats.

Knowing that the number S must be an integer, and when we divide T into groups of 4 and 6 we end with no empty seats, this means that T can be divided by 4 and by 6.

This means that T is a common multiple of 4 and 6

Now, we also know that 25 < T < 45.

Then let's see which ones are the multiples of 4 between 25 and 45.

4*7 = 28

4*8 = 32

4*9 = 36

4*10 = 40

4*11 = 44.

Now, the multiples of 6 in that range are:

6*5 = 30

6*6 = 36

6*7 = 42.

You can see that 36 is a common multiple, other way to see it is:

4*9 = (2*2)*(3*3) = 2*2*3*3 = (2*3)*(2*3) = 6*6

So the numer of tourist must be 36.

the probability is 0

step-by-step explanation: