A 160 ft. long wire has a resistance of 16.2 12. What would the resistance of 8 ft. of wire be?

Resistance = 0.8106 ohms.

Step-by-step explanation:

Electrical resistance is proportional to the length of a wire.

The relationship between resistance and length of a wire can be expressed as;

L1/R1 = L2/R2

Let L1 = 160 ft, R1 = 16.212 ohms

L2 = 8ft, R2 = ?

Substitutes all the parameters values into the formula

160/16.212 = 8/R2

Cross multiply

160R2 = 129.696

R2 = 129.696/160

R2 = 0.8106 ohms.

Therefore, the resistance of 8 ft. of wire will be 0.8106 ohms.

the answer is c

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.