How many integers are between sqrt 37 and 5*sqrt 11?

There are 10 integers between the given values

Step-by-step explanation:

We start by finding approximations of the two real values given that include square roots of non-perfect-square numbers:

then this point is located in between the integers 6 and 7 on the x-axis.

therefore, it is located between the integers 16 and 17 on the number line.

Then between , and , we have the following integers:

7, 8, 9, 10, 11, 12, 13, 14, 15, 16.

That is 10 integers

yeah and the opposite of cheating is studying ( you should try it some time)

step-by-step explanation:

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.