Find the equation of the line whose slope is 2 and which passes through the point (-2, 4).

Equation of a line is y = mx + c

where m = slope and c = y intercept

Using point ( -2 , 4) and m = 2

Equation of the line is

y - 4 = 2(x + 2)

y - 4 = 2x + 4

y = 2x + 4 + 4

y = 2x + 8

Hope this helps.

Equation of a line passing through (-2, 4) and slope '2' will be,

y = 2x + 8

Given in the question,

Equation of a line passing through a point (h, k) and slope 'm' is given by the equation,

y - k = m(x - h)

Substitute the values in the given equation,

y - 4 = 2[x - (-2)]

y - 4 = 2(x + 2)

y = 2x + 4 + 4

y = 2x + 8

       Therefore, equation of the line passing through (=2, 4) and slope '2' will be y = 2x + 8

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