Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 5 units long. Point C is on the line x = −2. If the area of ΔABC is 12.5 square units, then find a possible y-coordinate of point C. 5 6 7 8

Step-by-step explanation:

Segment AB is on the line y = 2 which is a horizontal line. Point C is on the line x = -2, which is a vertical line. These 2 lines will cross each other and form a right angle...the right angle in the right triangle in question. The formula for the area of a triangle is

The segment AB, being a horizontal line, is the base of our triangle and point C is somewhere on the height. If we can find the height of the triangle, we can add or subtract that height from y = 2 to get the possible y coordinate of point C. We already know the x coordinate (it's -2).

and

25 = 5h so

h = 5. That means that we can either add 5 to the y coordinate of 2, or we can subtract 5 from the y coordinate of 2 to get the possible y coordinate of point C.

2 + 5 = 7 so the coordinate for C could be (-2, 7) or

2 - 5 = -3 so the coordinate for C could also be (-2, -3).

Since -3 is not in our choices but 7 is, the one you want is 7.

20

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it