Given a square with two vertices of one side located at -5,-3 and -5,12 in square units what is its area

Step-by-step explanation:

Lets find the distance (the side length of the square)

D=sqrt((x2-x1)^(2)+(y2-y1)^(2))

plug in the coordinates:

D=sqrt((-5-(-5))^(2)+(12-(-3))^(2))

D=sqrt(0^(2)+15^(2))

D=sqrt(15^(2))

D=15

Area of a square is side length squared

A=s^2

A=15^2

A=225 units squared

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

4038

step-by-step explanation:

pleaze mark brainliest!