The probability that a person in the United States has type B+ blood is 12%. Three unrelated people in the United States are selected at random. Complete parts (a) through (d). (a) Find the probability that all three have type B+ blood. The probability that all three have type B+ blood is nothing. (Round to six decimal places as needed.)

The probability that all three have type B+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

The probability that a person in the United States has type B+ blood is 12%.

This means that

Three unrelated people in the United States are selected at random.

This means that

Find the probability that all three have type B+ blood.

This is P(X = 3).

The probability that all three have type B+ blood is 0.001728

answer: your answer is a

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)