It takes 22 hours for a hosepipe with a flow of 12 litres per minute to fill a swimming pool. How long will it take if its flow is reduced to 5 litres per minute?

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

Step-by-step explanation:

The volume of the swimming pool can be written as;

Volume V = flow rate × time

V = R×t

V = R1×t1 = R2×t2

R1×t1 = R2×t2

t2 = R1×t1/R2 1

Given;

Flow rate R1 = 12 litres per minute

Flow rate R2 = 5 litres per minute

time t1 = 22 hours

Substituting the given values into equation 1;

t2 = R1×t1/R2 = 12×22/5

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.

step-by-step explanation:

in which figure is point g a centroid