The table shows the battery lives, in hours, of ten Brand A batteries and ten Brand B batteries. Battery Life (hours)
Brand A
Brand B
22.5 17.0 21.0 23.0 22.0 18.5 22.5 20.0 19.0
20.0 19.5 20.5 16.5 14.0 17.0 11.0 19.5 21.0
23.0
12.0
Which would be the best measure of variability to use to compare the data?
Only Brand A data is symmetric, so standard deviation is the best measure to compare variability.
Only Brand B data is symmetric, so the median is the best measure to compare variability.
Both distributions are symmetric, so the mean is the best measure to compare variability.
Both distributions are skewed left, so the interquartile range is the best measure to compare variability

D. Both distributions are skewed left, so the interquartile range is the best measure to compare variability.

Step-by-step explanation:

Plotting the data roughly shows that the data is skewed to the left. In other words, data is skewed negatively and that the long tail will be on the negative side of the peak.

In such a scenario, interquartile range is normally the best measure to compare variations of data.

Therefore, the last option is the best for the data provided.

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D: Both distributions are skewed left, so the interquartile range is the best measure to compare variability.  

Step-by-step explanation:

edg2020

one set of data has more variation than the other. hope this !

answer: what is the question you're trying to ask?

step-by-step explanation: