Two functions are given below: f(x) and h(x). State the axis of symmetry for each function and explain how to find it

f(x) on x = 4

h(x) on x = -2

Step-by-step explanation:

for h(x) the axis of symmetry is x = -2 based on the graph

for f(x) = -2(x-4)² + 2 we must find for x intercept so take f(x) = 0

0 = -2(x-4)² + 2

-2 = -2(x-4)²

-2/-2 = (x-4)²

1 = (x-4)²

x-4 = √1

x-4 = 1 and x-4 = -1

so

x - 4 = 1

x = 5

x - 4 = -1

x = 3

so x intercept occured in x = 3 and x = 5

so the symmetry axis is in the middle x =4

(actually there's an easiest way, you can find the x axis from the form of y = a(x+b)² + c. The x-axis must be -b)

is there a picture

step-by-step explanation:

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step-by-step explanation:

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