Which graph shows the equation c = 10+ 3t, where c is the total cost of going to the carnival and t is the number of $3 tickets purchased? On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). A straight line with a positive slope begins at point (0, 10) and ends at point (6, 27). On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). Solid circles are at points (0, 10), (1, 14), (2, 16), (3, 19), (4, 22), (5, 25), (6, 28). On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). A straight line with a positive slope begins at point (0, 10) and ends around point (6, 60). On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). Solid circles are at points (0, 3), (1, 13), (2, 24), (3, 34), (4, 43), (5, 54).

The most correct option is;

On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). Solid circles at points (0, 10), (1, 14), (2. 16), (3, 19), (4, 22), (5, 25), (6, 28)

Step-by-step explanation:

The equation is c = 10 + 3·t

When we substitute t = 0 we have the y-intercept given by c = 10 + 3 × 0 = 10

When we substitute c = 0 we have the x-intercept given by 0 = 10 + 3 × t

t = -10/3

Which gives the graph in slope and intercept form as c = 3·t + 10, where 3 is the slope

Given the accuracy of the data points, the graph with solid circles at points (0, 10), (1, 14), (2. 16), (3, 19), (4, 22), (5, 25), (6, 28) has the slope given by (28 - 10)/(6 - 0) =3 Which agrees with the above solution. therefore, the most correct option is On a coordinate plane, the x-axis shows number of tickets sold (t) and the y-axis shows total cost of going to carnival (c). Solid circles at points (0, 10), (1, 14), (2. 16), (3, 19), (4, 22), (5, 25), (6, 28)

da freeck kinda math is this just drop out

step-by-step explanation: