I’ve been stuck for an hour please help!

3√13

According to the Pythagoras Theoram,

z² = y²+(9)²> (1)

Again , (13)²=x²+z²

so, z² = 169-x² > (2)

Now, x² = y²+(4)²

=> y² = x²-16>(3)

Comparing 1 and 2

y²+81 = 169-x²

From eq 3

x² -16 +81= 169-x²

2x² + 65 = 169

2x² = 169 -65

2x² = 104

x²= 104/2 = 52

From eq 2

z² = 169-x²

z² = 169-52

z² = 117

z= √117

z= 3√13

divide by 5

step-by-step explanation:

60/5 = 12

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1