*Quadratic equations*

Solve
(i) (x+3)(x-4)=0
(ii) (2x-3)(x-1) =0

Step-by-step explanation:

hello,

ab = 0 <=> a = 0 or b = 0

so

(x+3)(x-4)=0 <=> x+3 = 0 or x-4 = 0 <=> x = -3 or x = 4

(2x-3)(x-1)=0 <=> 2x-3=0 or x-1 = 0 <=> x = 3/2 or x = 1

hope this helps

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

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and if they dont well then thats less customers for them in a less profitable way

plz mark brainliest