What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)? y = 2 x + 33
y= *x+36
y = 4x - 16
y = 4x + 16

  y = 4x +16

Step-by-step explanation:

The given equation is in "point-slope" form:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

The slope of the given line is m=4. This is the same slope as any parallel line.

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The line you want can be written in the same point-slope form as ...

  y -32 = 4(x -4)

Rearranging, we have ...

  y = 4x -16 +32 . . . . . add 32, eliminate parentheses

  y = 4x +16 . . . . . . . . collect terms

2 is the final ! : )

c(x)= 6x + 3

step-by-step explanation: