Replace the letters with digits( the same letters represent the same digits) ABC +ACB=BCA

A = 4

B = 5

C = 9

ABC + ACB = CBA is then

459 + 495 = 954

Step-by-step explanation:

Working with

ABC + ACB = BCA,

There seems to be no feasible solution, but upon checking online, the correct question was obtained to be

ABC + ACB = CBA,

where A, B and C represent different digits

A B C +

A C B

C B A

So, for the units column

C + B = A

or

C + B = 10 + A

For the tens column

There are four possibilities

B + C = B

OR

1 + B + C = B

OR

B + C = 10 + B

OR

1 + B + C = 10 + B

Checking the equations one at a time

- If B + C = B, then C = 0

If C = 0, then units column equation 1, C + B = A, will not work because A, B, and C must stand for three different digits and B ≠ A.

If C = 0, then units column equation 2, C + B = 10 + A, will not work because B must stand for a single digit, B ≠ 10 + A

Therefore, tens column equation 1, B + C = B is not valid.

- If 1 + B + C = B, then C = -1

C must be a positive integer.

Therefore, tens column equation 2, 1 + B + C = B is not valid.

- If B + C = 10 + B

C cannot be equal to 10, as it is given that C is a single digit number.

Therefore, tens column equation 3, B + C = 10 + B, is not valid.

- If 1 + B + C = 10 + B

C = 9

Hence, this is the valid equation.

Our equation becomes

A B 9 +

A 9 B

9 B A

For the hundred's column, there is only one possibility.

Hundred's column equation 1:

since C is an odd number, the equation for the hundred's column is:

1 + A + A = C

1 + A + A = 9

therefore, A = 4

Our equation becomes

4 B 9 +

4 9 B

9 B 4

Solve for B using units column equation 2:

C + B = 10 + A

9 + B = 10 + 4

B = 5

Our final equation is then

4 5 9 +

4 9 5

9 5 4

Hope this Helps!!!

how is that middle school

step-by-step explanation:

(a) the volume of the cone is 20/3 in3

hence, option a is correct.