Find the solution to the system of equations. B
x - 2y - z= 4
x + 3y + z = -3
y + 5z = 17
O A. x= 2, y = -3, z = 4
B. x = 4, y=-3, z = 2
O C. x = 2, y = 7, z = 2
O D. x = 2, y = 6, z = 5

The answer is option A.

Hope this helps

the answer is true.

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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