The point B is at the centre of the circle. The pints P and Q are in the circumference of the circle. Calculate the area of the shaded sector. Take pi to be 3.142 in your working. Give your final answer to 1 dp.

24.7cm^2

Step-by-step explanation:

Line PQ = 5.413590865cm

BQ = 9cm

Angle BPQ =  

5.413590865² = 9² + 9² - 2 × 9 × 9 × cos(x)

29.30696605 = 81 + 81 - 162 × cos(x)  

29.30696605 = 162 - 162 × cos(x)

-132.693034 = -162 × cos(x)

cos(x) = 0.8190928022

x = 35.00591739˚

Area of sector = 24.7cm^2

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's