What are the zeros of the polynomial function F(x) = x^3 - 5x^2 - 6x?
A. X= -2, x = 0, and x = 3
B. x = -1, x = 0, and x = 6
C. x = -3, x = 0, and x = 2
D. x = -6, x = 0, and x = 1

B

Step-by-step explanation:

F(x) = x^3 - 5x^2 - 6x

F(x)=x(x^2-5x-6)

F(x)=x(x-6)(x+1)

So, x=0,-1,6

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

yes. we do proportions in probabilities.